1. What is the IUPAC name of the compound K2[Cr(NO)(CN)4 (NH3)]. Spin magnetic moment of the complex is 1.73 B.M.
Ans . To find the
IUPAC name of the given complex, the oxidation state of Cr must be known to us.
Here,
the magnetic moment of the complex is given. So by using the following formula,
µ=√[n(n+2)]
where
µ is magnetic moment and n is number of unpaired electrons, we get
1.73=√[n(n+2)]
By
hit and trial method, n=1
So,
the oxidation state of Cr in the complex is +1, i.e. Cr is present as Cr(I) in
the given complex.
Thus, the IUPAC name of the
complex is potassium aminetetracyanonitrosochromate(I).
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